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2.7x^2+40x+6.5=0
a = 2.7; b = 40; c = +6.5;
Δ = b2-4ac
Δ = 402-4·2.7·6.5
Δ = 1529.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-\sqrt{1529.8}}{2*2.7}=\frac{-40-\sqrt{1529.8}}{5.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+\sqrt{1529.8}}{2*2.7}=\frac{-40+\sqrt{1529.8}}{5.4} $
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